Algebraic data types in Java.
Aloso
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No it’s not, it is 100% a unit type (except it’s not really a type, since you can only use it as return type and nowhere else)

It’s not possible to instantiate or assign, which is more like a never type than a unit; and it is not possible to define new types with the same properties, which is also more like bottom than unit. But you’re right that it’s not actually a true never type since it can’t represent function divergence.

I think the truth is just that Java’s type system isn’t very mathematically disciplined.

Aloso
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1Y

It’s not possible to instantiate or assign, which is more like a never type than a unit

Actually, this is because void is not a type, it is just a keyword, a placeholder used instead of the return type when a function doesn’t return anything.

If it were a bottom type, that would mean that a method returning void must diverge, which is simply not true.

Also, if it were a bottom type, it would be possible to write an “unreachable” method

void unreachable(void bottom) {
    return bottom;
}

Even though it couldn’t be called, it should be possible to define it, if void was a bottom type. But it is not, because void isn’t a bottom type, it’s no type at all.

The post has been edited; it looks like someone on reddit made essentially the same point. You’re right of course that void isn’t a true type in Java, but the post now also discusses Void, which I suppose just shows how void infects the type system despite not being a type.

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