I used the debugger to examine this code but not understanding a couple areas.
int main(void)
{
int height = get_int("Height: ");
draw(height);
}
void draw(int n)
{
if (n <= 0)
{
return;
}
draw(n - 1);
for (int i = 0; i < n; i++)
{
printf("#");
}
printf("\n");
}
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No, the moment that draw(9) is called, draw(10) goes on pause while draw(9) runs, which pauses when it calls draw(8) … which repeats (or recurses) until draw(0) gets called. Then it returns which returns to draw(1). The draw(1) un-pauses and does the #\n bit and returns to draw(2), which un-pauses and does ##\n and so forth until draw(10) does ##########\n
Gotcha. Thanks for the explanation.