SOLUTION:

Here is the solution I came up with:

pub struct Configuration {}

impl Configuration {
    fn get std::str::FromStr>() -> Result {
        Ok(T::from_str("1234");
    }
}

fn main() {
    let my_conf_val = Configuration::get();
}

It may be possible to use the Any trait to “launder” the value by first casting it to &Any and then downcasting it to the generic type.

let any_value = match tmp_value {
    serde_json::Value::Number(x) => x as &Any,
    // ...
};

let maybe_value = any_value.downcast_ref::< T >();

I haven’t tested it, so I may have missed something.

Edit: to be clear, this will not actually let you return multiple types, but let the caller decide which type to expect. I assumed this was your goal.

I see two options immediately:

Make the function generic and return result(T, err), where T is the generic typed supplied by the caller (turbo fish syntax). Not sure if it will compile though.

Use whatever serve uses under the hood. They obviously have some way that allows them to return an arbitrary type. Alternatively implement it yourself by creating an enum that can be either string, int or bool. Will require matching by the caller after the function returns.

I know in e.g. java you regularly do if x.instanceof(y), but rust lends itself really badly to this type of programming.

Well how do you want to use said get function?

let x = config.get("key").await;

So what type should x have?

No. You can only return a single type from the function. You could return the serde_json::Value though so that the code calling this function can get the value it needs itself